#{Theorem}: _ f#: [ ~a, ~b ] --> &reals. continuous, then
We say that f is #~{bounded} on [ ~a, ~b ] if the range of f is bounded.
So the first part of the theorem says that a continuous functions is bounded.
#{Proof of Theorem}:
To be provided
f#: [ ~a, ~b ] --> &reals., _ f continuous on [ ~a, ~b ] , _ then the range of _ f _ is a closed interval [ ~{&alpha.}, ~{&beta.} ] &subseteq. &reals.
f continuous on [ ~a, ~b ] _ and _ f ( ~a ) , f ( ~b ) _ have opposite signs, _ then the equation _ f ( ~x ) = 0 _ has at least one solution in [ ~a, ~b ]
f continuous on [ ~a, ~b ] _ with range _ [ ~{&alpha.}, ~{&beta.} ] , _ then if _ f _ is strictly increasing, it has a continuous, strictly increasing inverse function, _
g#: [ ~{&alpha.}, ~{&beta.} ] --> &reals. , _ with range [ ~a, ~b ].